Base | Representation |
---|---|
bin | 1000001010011100010… |
… | …1010001100010111011 |
3 | 111101222201022102012212 |
4 | 2002213011101202323 |
5 | 4244203441144011 |
6 | 144232031325335 |
7 | 13063221305654 |
oct | 2024705214273 |
9 | 441881272185 |
10 | 140242131131 |
11 | 54527032913 |
12 | 2321a98084b |
13 | 102bcaaab5b |
14 | 6b0585a52b |
15 | 39ac0ee08b |
hex | 20a71518bb |
140242131131 has 2 divisors, whose sum is σ = 140242131132. Its totient is φ = 140242131130.
The previous prime is 140242131097. The next prime is 140242131203. The reversal of 140242131131 is 131131242041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 140242131131 - 230 = 139168389307 is a prime.
It is a super-2 number, since 2×1402421311312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 140242131097 and 140242131106.
It is not a weakly prime, because it can be changed into another prime (140242136131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70121065565 + 70121065566.
It is an arithmetic number, because the mean of its divisors is an integer number (70121065566).
Almost surely, 2140242131131 is an apocalyptic number.
140242131131 is a deficient number, since it is larger than the sum of its proper divisors (1).
140242131131 is an equidigital number, since it uses as much as digits as its factorization.
140242131131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 140242131131 its reverse (131131242041), we get a palindrome (271373373172).
The spelling of 140242131131 in words is "one hundred forty billion, two hundred forty-two million, one hundred thirty-one thousand, one hundred thirty-one".
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