Base | Representation |
---|---|
bin | 101001110010111… |
… | …1011100001001001 |
3 | 10121201221221112012 |
4 | 1103211323201021 |
5 | 10333011431131 |
6 | 351055225305 |
7 | 46516434314 |
oct | 12345734111 |
9 | 3551857465 |
10 | 1402452041 |
11 | 65a713a81 |
12 | 331818235 |
13 | 1947298a3 |
14 | d438d97b |
15 | 831cb52b |
hex | 5397b849 |
1402452041 has 2 divisors, whose sum is σ = 1402452042. Its totient is φ = 1402452040.
The previous prime is 1402451989. The next prime is 1402452047. The reversal of 1402452041 is 1402542041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 850014025 + 552438016 = 29155^2 + 23504^2 .
It is a cyclic number.
It is not a de Polignac number, because 1402452041 - 218 = 1402189897 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1402451998 and 1402452016.
It is not a weakly prime, because it can be changed into another prime (1402452047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701226020 + 701226021.
It is an arithmetic number, because the mean of its divisors is an integer number (701226021).
Almost surely, 21402452041 is an apocalyptic number.
It is an amenable number.
1402452041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1402452041 is an equidigital number, since it uses as much as digits as its factorization.
1402452041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1280, while the sum is 23.
The square root of 1402452041 is about 37449.3263090272. The cubic root of 1402452041 is about 1119.3416733316.
Adding to 1402452041 its reverse (1402542041), we get a palindrome (2804994082).
Subtracting 1402452041 from its reverse (1402542041), we obtain a square (90000 = 3002).
The spelling of 1402452041 in words is "one billion, four hundred two million, four hundred fifty-two thousand, forty-one".
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