14025504360053 has 4 divisors (see below), whose sum is σ = 14025700015488. Its totient is φ = 14025308704620.

The previous prime is 14025504360047. The next prime is 14025504360121. The reversal of 14025504360053 is 35006340552041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14025504360053 - 2⁴ = 14025504360037 is a prime.

It is a super-3 number, since 3×14025504360053³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14025504359989 and 14025504360016.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14025504360013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97720151 + ... + 97863572.

It is an arithmetic number, because the mean of its divisors is an integer number (3506425003872).

Almost surely, 2^{14025504360053} is an apocalyptic number.

It is an amenable number.

14025504360053 is a deficient number, since it is larger than the sum of its proper divisors (195655435).

14025504360053 is an equidigital number, since it uses as much as digits as its factorization.

14025504360053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 195655434.

The product of its (nonzero) digits is 216000, while the sum is 38.

The spelling of 14025504360053 in words is "fourteen trillion, twenty-five billion, five hundred four million, three hundred sixty thousand, fifty-three".