Base | Representation |
---|---|
bin | 1000001010101010001… |
… | …0111000011010010011 |
3 | 111102010202121211212001 |
4 | 2002222202320122103 |
5 | 4244313324133042 |
6 | 144241504414431 |
7 | 13064525141236 |
oct | 2025242703223 |
9 | 442122554761 |
10 | 140300224147 |
11 | 54556900a76 |
12 | 23236317417 |
13 | 102cbb3ab15 |
14 | 6b0d45d41d |
15 | 39b2276bb7 |
hex | 20aa8b8693 |
140300224147 has 2 divisors, whose sum is σ = 140300224148. Its totient is φ = 140300224146.
The previous prime is 140300224091. The next prime is 140300224151. The reversal of 140300224147 is 741422003041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 140300224147 - 27 = 140300224019 is a prime.
It is not a weakly prime, because it can be changed into another prime (140300224247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70150112073 + 70150112074.
It is an arithmetic number, because the mean of its divisors is an integer number (70150112074).
Almost surely, 2140300224147 is an apocalyptic number.
140300224147 is a deficient number, since it is larger than the sum of its proper divisors (1).
140300224147 is an equidigital number, since it uses as much as digits as its factorization.
140300224147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5376, while the sum is 28.
Adding to 140300224147 its reverse (741422003041), we get a palindrome (881722227188).
The spelling of 140300224147 in words is "one hundred forty billion, three hundred million, two hundred twenty-four thousand, one hundred forty-seven".
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