Base | Representation |
---|---|
bin | 10100011010110000000… |
… | …101000000011011101011 |
3 | 11222010200101110222121121 |
4 | 110122300011000123223 |
5 | 140442034020103003 |
6 | 2552325330320111 |
7 | 203241313315351 |
oct | 24326005003353 |
9 | 4863611428547 |
10 | 1403113441003 |
11 | 4a1069a5a62a |
12 | 1a7b23a29037 |
13 | a240b959a61 |
14 | 4bca7d017d1 |
15 | 26771660cbd |
hex | 146b01406eb |
1403113441003 has 4 divisors (see below), whose sum is σ = 1416226650840. Its totient is φ = 1390000231168.
The previous prime is 1403113440959. The next prime is 1403113441021. The reversal of 1403113441003 is 3001443113041.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1403113441003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1403113441033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6556604758 + ... + 6556604971.
It is an arithmetic number, because the mean of its divisors is an integer number (354056662710).
Almost surely, 21403113441003 is an apocalyptic number.
1403113441003 is a deficient number, since it is larger than the sum of its proper divisors (13113209837).
1403113441003 is a wasteful number, since it uses less digits than its factorization.
1403113441003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13113209836.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1403113441003 its reverse (3001443113041), we get a palindrome (4404556554044).
The spelling of 1403113441003 in words is "one trillion, four hundred three billion, one hundred thirteen million, four hundred forty-one thousand, three".
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