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140312320053 = 346770773351
BaseRepresentation
bin1000001010101101000…
…1000001100000110101
3111102011121101101022120
42002223101001200311
54244324423220203
6144243015550153
713065033020253
oct2025321014065
9442147341276
10140312320053
1154562712894
122323a38b359
13103014b4669
146b10ccb5d3
1539b3365b53
hex20ab441835

140312320053 has 4 divisors (see below), whose sum is σ = 187083093408. Its totient is φ = 93541546700.

The previous prime is 140312320051. The next prime is 140312320091. The reversal of 140312320053 is 350023213041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140312320053 - 21 = 140312320051 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140312320051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23385386673 + ... + 23385386678.

It is an arithmetic number, because the mean of its divisors is an integer number (46770773352).

Almost surely, 2140312320053 is an apocalyptic number.

It is an amenable number.

140312320053 is a deficient number, since it is larger than the sum of its proper divisors (46770773355).

140312320053 is an equidigital number, since it uses as much as digits as its factorization.

140312320053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 46770773354.

The product of its (nonzero) digits is 2160, while the sum is 24.

Adding to 140312320053 its reverse (350023213041), we get a palindrome (490335533094).

The spelling of 140312320053 in words is "one hundred forty billion, three hundred twelve million, three hundred twenty thousand, fifty-three".

Divisors: 1 3 46770773351 140312320053