Base | Representation |
---|---|
bin | 10100011010110001101… |
… | …010110101010011100010 |
3 | 11222010202020201010200100 |
4 | 110122301222311103202 |
5 | 140442112333242424 |
6 | 2552332122403230 |
7 | 203242056232005 |
oct | 24326152652342 |
9 | 4863666633610 |
10 | 1403140134114 |
11 | 4a1083031554 |
12 | 1a7b30960516 |
13 | a24143447b4 |
14 | 4bcab68d53c |
15 | 26773b84dc9 |
hex | 146b1ab54e2 |
1403140134114 has 24 divisors (see below), whose sum is σ = 3040375133952. Its totient is φ = 467676735480.
The previous prime is 1403140134107. The next prime is 1403140134161. The reversal of 1403140134114 is 4114310413041.
1403140134114 is a `hidden beast` number, since 1 + 4 + 0 + 314 + 0 + 1 + 341 + 1 + 4 = 666.
It is a super-2 number, since 2×14031401341142 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2816914 + ... + 3277389.
It is an arithmetic number, because the mean of its divisors is an integer number (126682297248).
Almost surely, 21403140134114 is an apocalyptic number.
1403140134114 is an abundant number, since it is smaller than the sum of its proper divisors (1637234999838).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1403140134114 is a wasteful number, since it uses less digits than its factorization.
1403140134114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6107102 (or 6107099 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 27.
Adding to 1403140134114 its reverse (4114310413041), we get a palindrome (5517450547155).
The spelling of 1403140134114 in words is "one trillion, four hundred three billion, one hundred forty million, one hundred thirty-four thousand, one hundred fourteen".
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