14031401401411 has 4 divisors (see below), whose sum is σ = 14410628466352. Its totient is φ = 13652174336472.

The previous prime is 14031401401399. The next prime is 14031401401447. The reversal of 14031401401411 is 11410410413041.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14031401401411 - 2⁵ = 14031401401379 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14031401401471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 189613532415 + ... + 189613532488.

It is an arithmetic number, because the mean of its divisors is an integer number (3602657116588).

Almost surely, 2^{14031401401411} is an apocalyptic number.

14031401401411 is a deficient number, since it is larger than the sum of its proper divisors (379227064941).

14031401401411 is an equidigital number, since it uses as much as digits as its factorization.

14031401401411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 379227064940.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 14031401401411 its reverse (11410410413041), we get a palindrome (25441811814452).

The spelling of 14031401401411 in words is "fourteen trillion, thirty-one billion, four hundred one million, four hundred one thousand, four hundred eleven".