Base | Representation |
---|---|
bin | 1100110000101111000011… |
… | …0000001000111110010011 |
3 | 1211200101111112222010022011 |
4 | 3030023300300020332103 |
5 | 3314342302444341433 |
6 | 45501534240123351 |
7 | 2645510142006661 |
oct | 314136060107623 |
9 | 54611445863264 |
10 | 14031402340243 |
11 | 451a7589066a2 |
12 | 16a7468306557 |
13 | 7aa203a06a72 |
14 | 3671a2c37c31 |
15 | 194ec7bd03cd |
hex | cc2f0c08f93 |
14031402340243 has 2 divisors, whose sum is σ = 14031402340244. Its totient is φ = 14031402340242.
The previous prime is 14031402340223. The next prime is 14031402340253. The reversal of 14031402340243 is 34204320413041.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14031402340243 is a prime.
It is not a weakly prime, because it can be changed into another prime (14031402340213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7015701170121 + 7015701170122.
It is an arithmetic number, because the mean of its divisors is an integer number (7015701170122).
Almost surely, 214031402340243 is an apocalyptic number.
14031402340243 is a deficient number, since it is larger than the sum of its proper divisors (1).
14031402340243 is an equidigital number, since it uses as much as digits as its factorization.
14031402340243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 14031402340243 its reverse (34204320413041), we get a palindrome (48235722753284).
The spelling of 14031402340243 in words is "fourteen trillion, thirty-one billion, four hundred two million, three hundred forty thousand, two hundred forty-three".
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