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140320411315 = 5789367122743
BaseRepresentation
bin1000001010101110111…
…1111000111010110011
3111102012011121110102221
42002223233320322303
54244334011130230
6144243505221511
713065161550040
oct2025357707263
9442164543387
10140320411315
1154567239987
1223241031897
13103030884a6
146b11dd61c7
1539b3e1327a
hex20abbf8eb3

140320411315 has 32 divisors (see below), whose sum is σ = 195133501440. Its totient is φ = 94878584064.

The previous prime is 140320411163. The next prime is 140320411321. The reversal of 140320411315 is 513114023041.

It is a cyclic number.

It is not a de Polignac number, because 140320411315 - 231 = 138172927667 is a prime.

It is a super-2 number, since 2×1403204113152 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 140320411315.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1081834 + ... + 1204576.

It is an arithmetic number, because the mean of its divisors is an integer number (6097921920).

Almost surely, 2140320411315 is an apocalyptic number.

140320411315 is a deficient number, since it is larger than the sum of its proper divisors (54813090125).

140320411315 is a wasteful number, since it uses less digits than its factorization.

140320411315 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 123211.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 140320411315 its reverse (513114023041), we get a palindrome (653434434356).

The spelling of 140320411315 in words is "one hundred forty billion, three hundred twenty million, four hundred eleven thousand, three hundred fifteen".

Divisors: 1 5 7 35 89 367 445 623 1835 2569 3115 12845 32663 122743 163315 228641 613715 859201 1143205 4296005 10924127 45046681 54620635 76468889 225233405 315326767 382344445 1576633835 4009154609 20045773045 28064082263 140320411315