Base | Representation |
---|---|
bin | 1000001010101111011… |
… | …1100011100110011011 |
3 | 111102012022101120102011 |
4 | 2002223313203212123 |
5 | 4244340014434042 |
6 | 144244020250351 |
7 | 13065214620436 |
oct | 2025367434633 |
9 | 442168346364 |
10 | 140322421147 |
11 | 545683919a7 |
12 | 232418409b7 |
13 | 1030361023c |
14 | 6b1239a81d |
15 | 39b41ada17 |
hex | 20abde399b |
140322421147 has 2 divisors, whose sum is σ = 140322421148. Its totient is φ = 140322421146.
The previous prime is 140322421051. The next prime is 140322421177. The reversal of 140322421147 is 741124223041.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-140322421147 is a prime.
It is not a weakly prime, because it can be changed into another prime (140322421177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70161210573 + 70161210574.
It is an arithmetic number, because the mean of its divisors is an integer number (70161210574).
Almost surely, 2140322421147 is an apocalyptic number.
140322421147 is a deficient number, since it is larger than the sum of its proper divisors (1).
140322421147 is an equidigital number, since it uses as much as digits as its factorization.
140322421147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10752, while the sum is 31.
Adding to 140322421147 its reverse (741124223041), we get a palindrome (881446644188).
The spelling of 140322421147 in words is "one hundred forty billion, three hundred twenty-two million, four hundred twenty-one thousand, one hundred forty-seven".
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