140323120333 has 4 divisors (see below), whose sum is σ = 153079767648. Its totient is φ = 127566473020.

The previous prime is 140323120331. The next prime is 140323120351. The reversal of 140323120333 is 333021323041.

140323120333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 333021323041 = 11 ⋅30274665731.

It is a cyclic number.

It is not a de Polignac number, because 140323120333 - 2¹ = 140323120331 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140323120298 and 140323120307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140323120331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6378323641 + ... + 6378323662.

It is an arithmetic number, because the mean of its divisors is an integer number (38269941912).

Almost surely, 2^140323120333 is an apocalyptic number.

It is an amenable number.

140323120333 is a deficient number, since it is larger than the sum of its proper divisors (12756647315).

140323120333 is a wasteful number, since it uses less digits than its factorization.

140323120333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12756647314.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 140323120333 its reverse (333021323041), we get a palindrome (473344443374).

The spelling of 140323120333 in words is "one hundred forty billion, three hundred twenty-three million, one hundred twenty thousand, three hundred thirty-three".