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140324113 is a prime number
BaseRepresentation
bin10000101110100…
…10110100010001
3100210001012111101
420113102310101
5241410332423
621531344401
73322510126
oct1027226421
9323035441
10140324113
1172233646
123abb2101
13230c1a27
14148ca74d
15c4bc7ad
hex85d2d11

140324113 has 2 divisors, whose sum is σ = 140324114. Its totient is φ = 140324112.

The previous prime is 140324089. The next prime is 140324123. The reversal of 140324113 is 311423041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 131033809 + 9290304 = 11447^2 + 3048^2 .

It is an emirp because it is prime and its reverse (311423041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140324113 - 217 = 140193041 is a prime.

It is not a weakly prime, because it can be changed into another prime (140324123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70162056 + 70162057.

It is an arithmetic number, because the mean of its divisors is an integer number (70162057).

Almost surely, 2140324113 is an apocalyptic number.

It is an amenable number.

140324113 is a deficient number, since it is larger than the sum of its proper divisors (1).

140324113 is an equidigital number, since it uses as much as digits as its factorization.

140324113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 19.

The square root of 140324113 is about 11845.8479223735. The cubic root of 140324113 is about 519.6498048938.

Adding to 140324113 its reverse (311423041), we get a palindrome (451747154).

It can be divided in two parts, 14032 and 4113, that added together give a triangular number (18145 = T190).

The spelling of 140324113 in words is "one hundred forty million, three hundred twenty-four thousand, one hundred thirteen".