14032434111111 has 32 divisors (see below), whose sum is σ = 22391913707520. Its totient is φ = 8633807135712.

The previous prime is 14032434110899. The next prime is 14032434111161. The reversal of 14032434111111 is 11111143423041.

14032434111111 is a `hidden beast` number, since 1 + 4 + 0 + 3 + 2 + 434 + 111 + 111 = 666.

It is not a de Polignac number, because 14032434111111 - 2¹³ = 14032434102919 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14032434111161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1581231 + ... + 5528576.

It is an arithmetic number, because the mean of its divisors is an integer number (699747303360).

Almost surely, 2^{14032434111111} is an apocalyptic number.

14032434111111 is a deficient number, since it is larger than the sum of its proper divisors (8359479596409).

14032434111111 is a wasteful number, since it uses less digits than its factorization.

14032434111111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7115452 (or 7115446 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 27.

Adding to 14032434111111 its reverse (11111143423041), we get a palindrome (25143577534152).

The spelling of 14032434111111 in words is "fourteen trillion, thirty-two billion, four hundred thirty-four million, one hundred eleven thousand, one hundred eleven".