Base | Representation |
---|---|
bin | 11111111010000101011101… |
… | …011100111000010110010100 |
3 | 200101212111221001201001222020 |
4 | 133322011131130320112110 |
5 | 121343140424241023012 |
6 | 1214243104233133140 |
7 | 41362403564365404 |
oct | 3772053534702624 |
9 | 611774831631866 |
10 | 140331034314132 |
11 | 4079406a4a2042 |
12 | 138a511755a1b0 |
13 | 603c20cc9709c |
14 | 26920b5d98804 |
15 | 11354eb4d2a8c |
hex | 7fa15d738594 |
140331034314132 has 48 divisors (see below), whose sum is σ = 332039979048960. Its totient is φ = 46121369085792.
The previous prime is 140331034314131. The next prime is 140331034314167. The reversal of 140331034314132 is 231413430133041.
140331034314132 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 140331034314093 and 140331034314102.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (140331034314131) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 101118588 + ... + 102496979.
It is an arithmetic number, because the mean of its divisors is an integer number (6917499563520).
Almost surely, 2140331034314132 is an apocalyptic number.
140331034314132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
140331034314132 is an abundant number, since it is smaller than the sum of its proper divisors (191708944734828).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
140331034314132 is a wasteful number, since it uses less digits than its factorization.
140331034314132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 203616380 (or 203616378 counting only the distinct ones).
The product of its (nonzero) digits is 31104, while the sum is 33.
Adding to 140331034314132 its reverse (231413430133041), we get a palindrome (371744464447173).
The spelling of 140331034314132 in words is "one hundred forty trillion, three hundred thirty-one billion, thirty-four million, three hundred fourteen thousand, one hundred thirty-two".
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