Base | Representation |
---|---|
bin | 10100011010111011110… |
… | …100011001100100101001 |
3 | 11222011012010010020221021 |
4 | 110122323310121210221 |
5 | 140442434431222441 |
6 | 2552401044212441 |
7 | 203246224465120 |
oct | 24327364314451 |
9 | 4864163106837 |
10 | 1403310414121 |
11 | 4a1160165430 |
12 | 1a7b7999a121 |
13 | a24406c43b5 |
14 | 4bcc6136ab7 |
15 | 26783abd3d1 |
hex | 146bbd19929 |
1403310414121 has 32 divisors (see below), whose sum is σ = 1786906598400. Its totient is φ = 1070402402880.
The previous prime is 1403310414109. The next prime is 1403310414179. The reversal of 1403310414121 is 1214140133041.
It is a cyclic number.
It is not a de Polignac number, because 1403310414121 - 231 = 1401162930473 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1403311414121) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 310611 + ... + 1703848.
It is an arithmetic number, because the mean of its divisors is an integer number (55840831200).
Almost surely, 21403310414121 is an apocalyptic number.
1403310414121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
1403310414121 is a deficient number, since it is larger than the sum of its proper divisors (383596184279).
1403310414121 is a wasteful number, since it uses less digits than its factorization.
1403310414121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2014669.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1403310414121 its reverse (1214140133041), we get a palindrome (2617450547162).
The spelling of 1403310414121 in words is "one trillion, four hundred three billion, three hundred ten million, four hundred fourteen thousand, one hundred twenty-one".
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