Base | Representation |
---|---|
bin | 1100110000111001011110… |
… | …0101000001111110011011 |
3 | 1211200122201121120002201222 |
4 | 3030032113211001332123 |
5 | 3314414021003114232 |
6 | 45503120102002255 |
7 | 2645636406063134 |
oct | 314162745017633 |
9 | 54618647502658 |
10 | 14034201223067 |
11 | 45209647a07a3 |
12 | 16a7b0971638b |
13 | 7aa55b83264c |
14 | 36738a84ac8b |
15 | 1950dd798d12 |
hex | cc397941f9b |
14034201223067 has 2 divisors, whose sum is σ = 14034201223068. Its totient is φ = 14034201223066.
The previous prime is 14034201222983. The next prime is 14034201223093. The reversal of 14034201223067 is 76032210243041.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14034201223067 is a prime.
It is not a weakly prime, because it can be changed into another prime (14034201223967) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7017100611533 + 7017100611534.
It is an arithmetic number, because the mean of its divisors is an integer number (7017100611534).
Almost surely, 214034201223067 is an apocalyptic number.
14034201223067 is a deficient number, since it is larger than the sum of its proper divisors (1).
14034201223067 is an equidigital number, since it uses as much as digits as its factorization.
14034201223067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 35.
The spelling of 14034201223067 in words is "fourteen trillion, thirty-four billion, two hundred one million, two hundred twenty-three thousand, sixty-seven".
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