Base | Representation |
---|---|
bin | 10100011011000010011… |
… | …110100001100011000010 |
3 | 11222011110220022111202212 |
4 | 110123002132201203002 |
5 | 140443202030321010 |
6 | 2552420114342122 |
7 | 203252052123452 |
oct | 24330236414302 |
9 | 4864426274685 |
10 | 1403422120130 |
11 | 4a1208221848 |
12 | 1a7bab28a942 |
13 | a245a8a6124 |
14 | 4bcd6cd3d62 |
15 | 2678d7d6505 |
hex | 146c27a18c2 |
1403422120130 has 16 divisors (see below), whose sum is σ = 2526799907520. Its totient is φ = 561226605552.
The previous prime is 1403422120099. The next prime is 1403422120181. The reversal of 1403422120130 is 310212243041.
It is a junction number, because it is equal to n+sod(n) for n = 1403422120096 and 1403422120105.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17738870 + ... + 17817809.
It is an arithmetic number, because the mean of its divisors is an integer number (157924994220).
Almost surely, 21403422120130 is an apocalyptic number.
1403422120130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1403422120130 is a deficient number, since it is larger than the sum of its proper divisors (1123377787390).
1403422120130 is a wasteful number, since it uses less digits than its factorization.
1403422120130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 35560633.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 1403422120130 its reverse (310212243041), we get a palindrome (1713634363171).
The spelling of 1403422120130 in words is "one trillion, four hundred three billion, four hundred twenty-two million, one hundred twenty thousand, one hundred thirty".
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