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1403422120130 = 25394735556679
BaseRepresentation
bin10100011011000010011…
…110100001100011000010
311222011110220022111202212
4110123002132201203002
5140443202030321010
62552420114342122
7203252052123452
oct24330236414302
94864426274685
101403422120130
114a1208221848
121a7bab28a942
13a245a8a6124
144bcd6cd3d62
152678d7d6505
hex146c27a18c2

1403422120130 has 16 divisors (see below), whose sum is σ = 2526799907520. Its totient is φ = 561226605552.

The previous prime is 1403422120099. The next prime is 1403422120181. The reversal of 1403422120130 is 310212243041.

It is a junction number, because it is equal to n+sod(n) for n = 1403422120096 and 1403422120105.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17738870 + ... + 17817809.

It is an arithmetic number, because the mean of its divisors is an integer number (157924994220).

Almost surely, 21403422120130 is an apocalyptic number.

1403422120130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1403422120130 is a deficient number, since it is larger than the sum of its proper divisors (1123377787390).

1403422120130 is a wasteful number, since it uses less digits than its factorization.

1403422120130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35560633.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1403422120130 its reverse (310212243041), we get a palindrome (1713634363171).

The spelling of 1403422120130 in words is "one trillion, four hundred three billion, four hundred twenty-two million, one hundred twenty thousand, one hundred thirty".

Divisors: 1 2 5 10 3947 7894 19735 39470 35556679 71113358 177783395 355566790 140342212013 280684424026 701711060065 1403422120130