Base | Representation |
---|---|
bin | 1100110000111100101000… |
… | …1011010010110100001010 |
3 | 1211200201220202220020121112 |
4 | 3030033022023102310022 |
5 | 3314422240312124224 |
6 | 45503340224410322 |
7 | 2645666424405545 |
oct | 314171213226412 |
9 | 54621822806545 |
10 | 14035050114314 |
11 | 452125a995309 |
12 | 16a8105a769a2 |
13 | 7aa665673068 |
14 | 36742b4a185c |
15 | 19513d07c30e |
hex | cc3ca2d2d0a |
14035050114314 has 4 divisors (see below), whose sum is σ = 21052575171474. Its totient is φ = 7017525057156.
The previous prime is 14035050114289. The next prime is 14035050114317. The reversal of 14035050114314 is 41341105053041.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 12126991358689 + 1908058755625 = 3482383^2 + 1381325^2 .
It is a super-2 number, since 2×140350501143142 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (14035050114317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3508762528577 + ... + 3508762528580.
Almost surely, 214035050114314 is an apocalyptic number.
14035050114314 is a deficient number, since it is larger than the sum of its proper divisors (7017525057160).
14035050114314 is an equidigital number, since it uses as much as digits as its factorization.
14035050114314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7017525057159.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 14035050114314 its reverse (41341105053041), we get a palindrome (55376155167355).
The spelling of 14035050114314 in words is "fourteen trillion, thirty-five billion, fifty million, one hundred fourteen thousand, three hundred fourteen".
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