1403512313351 has 4 divisors (see below), whose sum is σ = 1403862932472. Its totient is φ = 1403161694232.

The previous prime is 1403512313341. The next prime is 1403512313353. The reversal of 1403512313351 is 1533132153041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1403512313351 is a prime.

It is a super-2 number, since 2×1403512313351² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1403512313353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 175303556 + ... + 175311561.

It is an arithmetic number, because the mean of its divisors is an integer number (350965733118).

Almost surely, 2^{1403512313351} is an apocalyptic number.

1403512313351 is a deficient number, since it is larger than the sum of its proper divisors (350619121).

1403512313351 is an equidigital number, since it uses as much as digits as its factorization.

1403512313351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 350619120.

The product of its (nonzero) digits is 16200, while the sum is 32.

Adding to 1403512313351 its reverse (1533132153041), we get a palindrome (2936644466392).

The spelling of 1403512313351 in words is "one trillion, four hundred three billion, five hundred twelve million, three hundred thirteen thousand, three hundred fifty-one".