Base | Representation |
---|---|
bin | 11111111010011000010001… |
… | …011010101111111011110011 |
3 | 200101221110001210002020000121 |
4 | 133322120101122233323303 |
5 | 121344003311240222233 |
6 | 1214300244440231111 |
7 | 41364020256004435 |
oct | 3772302132577363 |
9 | 611843053066017 |
10 | 140351233523443 |
11 | 407a1695413a58 |
12 | 138a901416b497 |
13 | 60410aba10147 |
14 | 26930708d8655 |
15 | 1135cce99d92d |
hex | 7fa6116afef3 |
140351233523443 has 2 divisors, whose sum is σ = 140351233523444. Its totient is φ = 140351233523442.
The previous prime is 140351233523383. The next prime is 140351233523497. The reversal of 140351233523443 is 344325332153041.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-140351233523443 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 140351233523443.
It is not a weakly prime, because it can be changed into another prime (140351233523143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70175616761721 + 70175616761722.
It is an arithmetic number, because the mean of its divisors is an integer number (70175616761722).
Almost surely, 2140351233523443 is an apocalyptic number.
140351233523443 is a deficient number, since it is larger than the sum of its proper divisors (1).
140351233523443 is an equidigital number, since it uses as much as digits as its factorization.
140351233523443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1555200, while the sum is 43.
Adding to 140351233523443 its reverse (344325332153041), we get a palindrome (484676565676484).
The spelling of 140351233523443 in words is "one hundred forty trillion, three hundred fifty-one billion, two hundred thirty-three million, five hundred twenty-three thousand, four hundred forty-three".
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