140352540313 has 2 divisors, whose sum is σ = 140352540314. Its totient is φ = 140352540312.

The previous prime is 140352540299. The next prime is 140352540343. The reversal of 140352540313 is 313045253041.

140352540313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 83225326144 + 57127214169 = 288488^2 + 239013^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140352540313 is a prime.

It is a super-3 number, since 3×140352540313³ (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (140352540343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70176270156 + 70176270157.

It is an arithmetic number, because the mean of its divisors is an integer number (70176270157).

Almost surely, 2^140352540313 is an apocalyptic number.

It is an amenable number.

140352540313 is a deficient number, since it is larger than the sum of its proper divisors (1).

140352540313 is an equidigital number, since it uses as much as digits as its factorization.

140352540313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 140352540313 its reverse (313045253041), we get a palindrome (453397793354).

The spelling of 140352540313 in words is "one hundred forty billion, three hundred fifty-two million, five hundred forty thousand, three hundred thirteen".