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140352540319 = 691203115109
BaseRepresentation
bin1000001010110110101…
…0011100111010011111
3111102021102001210011001
42002231222130322133
54244420222242234
6144251014011131
713066031623435
oct2025552347237
9442242053131
10140352540319
1154583393982
122324b946aa7
1310309927534
146b1639ad55
1539b6b5cd14
hex20ada9ce9f

140352540319 has 4 divisors (see below), whose sum is σ = 140555656120. Its totient is φ = 140149424520.

The previous prime is 140352540313. The next prime is 140352540343. The reversal of 140352540319 is 913045253041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140352540319 - 229 = 139815669407 is a prime.

It is a super-2 number, since 2×1403525403192 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140352540313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 101556864 + ... + 101558245.

It is an arithmetic number, because the mean of its divisors is an integer number (35138914030).

Almost surely, 2140352540319 is an apocalyptic number.

140352540319 is a deficient number, since it is larger than the sum of its proper divisors (203115801).

140352540319 is an equidigital number, since it uses as much as digits as its factorization.

140352540319 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 203115800.

The product of its (nonzero) digits is 64800, while the sum is 37.

The spelling of 140352540319 in words is "one hundred forty billion, three hundred fifty-two million, five hundred forty thousand, three hundred nineteen".

Divisors: 1 691 203115109 140352540319