140353113203541 has 48 divisors (see below), whose sum is σ = 243572239600000. Its totient is φ = 78245637845760.

The previous prime is 140353113203489. The next prime is 140353113203549. The reversal of 140353113203541 is 145302311353041.

140353113203541 is a `hidden beast` number, since 1 + 40 + 3 + 53 + 1 + 1 + 3 + 20 + 3 + 541 = 666.

It is not a de Polignac number, because 140353113203541 - 2²¹ = 140353111106389 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140353113203496 and 140353113203505.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140353113203549) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 220565416 + ... + 221200833.

Almost surely, 2^{140353113203541} is an apocalyptic number.

It is an amenable number.

140353113203541 is a deficient number, since it is larger than the sum of its proper divisors (103219126396459).

140353113203541 is an equidigital number, since it uses as much as digits as its factorization.

140353113203541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 441766347 (or 441766300 counting only the distinct ones).

The product of its (nonzero) digits is 64800, while the sum is 36.

Adding to 140353113203541 its reverse (145302311353041), we get a palindrome (285655424556582).

The spelling of 140353113203541 in words is "one hundred forty trillion, three hundred fifty-three billion, one hundred thirteen million, two hundred three thousand, five hundred forty-one".