1404004231231 has 8 divisors (see below), whose sum is σ = 1604713724064. Its totient is φ = 1203329103360.

The previous prime is 1404004231183. The next prime is 1404004231237. The reversal of 1404004231231 is 1321324004041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1404004231231 - 2²¹ = 1404002134079 is a prime.

It is a super-2 number, since 2×1404004231231² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1404004231196 and 1404004231205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1404004231237) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8503630 + ... + 8667163.

It is an arithmetic number, because the mean of its divisors is an integer number (200589215508).

Almost surely, 2^{1404004231231} is an apocalyptic number.

1404004231231 is a deficient number, since it is larger than the sum of its proper divisors (200709492833).

1404004231231 is a wasteful number, since it uses less digits than its factorization.

1404004231231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17182481.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1404004231231 its reverse (1321324004041), we get a palindrome (2725328235272).

The spelling of 1404004231231 in words is "one trillion, four hundred four billion, four million, two hundred thirty-one thousand, two hundred thirty-one".