Base | Representation |
---|---|
bin | 1100110001001111010001… |
… | …0100111001010011010001 |
3 | 1211201012211101021122021201 |
4 | 3030103310110321103101 |
5 | 3320013011333212432 |
6 | 45505524433351201 |
7 | 2646234403653223 |
oct | 314236424712321 |
9 | 54635741248251 |
10 | 14040052241617 |
11 | 4523397515616 |
12 | 16a9081108501 |
13 | 7aac81a97cbc |
14 | 367783958413 |
15 | 1953322a3ee7 |
hex | cc4f45394d1 |
14040052241617 has 2 divisors, whose sum is σ = 14040052241618. Its totient is φ = 14040052241616.
The previous prime is 14040052241549. The next prime is 14040052241627. The reversal of 14040052241617 is 71614225004041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9589235029201 + 4450817212416 = 3096649^2 + 2109696^2 .
It is a cyclic number.
It is not a de Polignac number, because 14040052241617 - 27 = 14040052241489 is a prime.
It is not a weakly prime, because it can be changed into another prime (14040052241627) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7020026120808 + 7020026120809.
It is an arithmetic number, because the mean of its divisors is an integer number (7020026120809).
Almost surely, 214040052241617 is an apocalyptic number.
It is an amenable number.
14040052241617 is a deficient number, since it is larger than the sum of its proper divisors (1).
14040052241617 is an equidigital number, since it uses as much as digits as its factorization.
14040052241617 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 53760, while the sum is 37.
Adding to 14040052241617 its reverse (71614225004041), we get a palindrome (85654277245658).
The spelling of 14040052241617 in words is "fourteen trillion, forty billion, fifty-two million, two hundred forty-one thousand, six hundred seventeen".
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