Base | Representation |
---|---|
bin | 1100110001001111011101… |
… | …0110111110110101110001 |
3 | 1211201012221221000112122012 |
4 | 3030103313112332311301 |
5 | 3320013112344321431 |
6 | 45505533452052305 |
7 | 2646235562300342 |
oct | 314236726766561 |
9 | 54635857015565 |
10 | 14040103120241 |
11 | 4523413206470 |
12 | 16a9096164095 |
13 | 7aac8c4a02b3 |
14 | 36778a6000c9 |
15 | 1953369a422b |
hex | cc4f75bed71 |
14040103120241 has 64 divisors (see below), whose sum is σ = 16301696311296. Its totient is φ = 11975769388800.
The previous prime is 14040103120207. The next prime is 14040103120243. The reversal of 14040103120241 is 14202130104041.
It is a cyclic number.
It is not a de Polignac number, because 14040103120241 - 214 = 14040103103857 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14040103120243) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3643938671 + ... + 3643942523.
It is an arithmetic number, because the mean of its divisors is an integer number (254714004864).
Almost surely, 214040103120241 is an apocalyptic number.
14040103120241 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
14040103120241 is a deficient number, since it is larger than the sum of its proper divisors (2261593191055).
14040103120241 is a wasteful number, since it uses less digits than its factorization.
14040103120241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6702.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 14040103120241 its reverse (14202130104041), we get a palindrome (28242233224282).
The spelling of 14040103120241 in words is "fourteen trillion, forty billion, one hundred three million, one hundred twenty thousand, two hundred forty-one".
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