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140401414131452 = 22277302112657803
BaseRepresentation
bin11111111011000111000000…
…011010100100111011111100
3200102010020120221202020020222
4133323013000122210323330
5121400314044004201302
61214335304053000512
741400444633100235
oct3773070032447374
9612106527666228
10140401414131452
11408109a6024521
12138b6899623138
136045a480076c6
14269567120008c
15113726a11bda2
hex7fb1c06a4efc

140401414131452 has 12 divisors (see below), whose sum is σ = 245702582745816. Its totient is φ = 70200676204080.

The previous prime is 140401414131443. The next prime is 140401414131469. The reversal of 140401414131452 is 254131414104041.

It is a super-2 number, since 2×1404014141314522 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4763183 + ... + 17420985.

It is an arithmetic number, because the mean of its divisors is an integer number (20475215228818).

Almost surely, 2140401414131452 is an apocalyptic number.

It is an amenable number.

140401414131452 is a deficient number, since it is larger than the sum of its proper divisors (105301168614364).

140401414131452 is a wasteful number, since it uses less digits than its factorization.

140401414131452 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15430828 (or 15430826 counting only the distinct ones).

The product of its (nonzero) digits is 30720, while the sum is 35.

Adding to 140401414131452 its reverse (254131414104041), we get a palindrome (394532828235493).

The spelling of 140401414131452 in words is "one hundred forty trillion, four hundred one billion, four hundred fourteen million, one hundred thirty-one thousand, four hundred fifty-two".

Divisors: 1 2 4 2773021 5546042 11092084 12657803 25315606 50631212 35100353532863 70200707065726 140401414131452