Base | Representation |
---|---|
bin | 1100110001010011010000… |
… | …0110001000101110111011 |
3 | 1211201022120221102210221222 |
4 | 3030110310012020232323 |
5 | 3320022204230130431 |
6 | 45510222532422255 |
7 | 2646303044511143 |
oct | 314246406105673 |
9 | 54638527383858 |
10 | 14041122114491 |
11 | 452389642297a |
12 | 16a931b47798b |
13 | 7ab0c262ab84 |
14 | 367845a93923 |
15 | 19539618857b |
hex | cc534188bbb |
14041122114491 has 2 divisors, whose sum is σ = 14041122114492. Its totient is φ = 14041122114490.
The previous prime is 14041122114427. The next prime is 14041122114527. The reversal of 14041122114491 is 19441122114041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14041122114491 - 26 = 14041122114427 is a prime.
It is a super-2 number, since 2×140411221144912 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14041122114791) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7020561057245 + 7020561057246.
It is an arithmetic number, because the mean of its divisors is an integer number (7020561057246).
Almost surely, 214041122114491 is an apocalyptic number.
14041122114491 is a deficient number, since it is larger than the sum of its proper divisors (1).
14041122114491 is an equidigital number, since it uses as much as digits as its factorization.
14041122114491 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 35.
The spelling of 14041122114491 in words is "fourteen trillion, forty-one billion, one hundred twenty-two million, one hundred fourteen thousand, four hundred ninety-one".
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