Base | Representation |
---|---|
bin | 10100011011101011100… |
… | …111000001000010001111 |
3 | 11222020020222211211000010 |
4 | 110123223213001002033 |
5 | 141001110211241421 |
6 | 2553012405404303 |
7 | 203305131610440 |
oct | 24335347010217 |
9 | 4866228754003 |
10 | 1404112212111 |
11 | 4a15318140a4 |
12 | 1a8162409693 |
13 | a253a85678b |
14 | 4bd6080d2c7 |
15 | 267ce19d076 |
hex | 146eb9c108f |
1404112212111 has 32 divisors (see below), whose sum is σ = 2145243760128. Its totient is φ = 800235970560.
The previous prime is 1404112212067. The next prime is 1404112212143. The reversal of 1404112212111 is 1112122114041.
It is not a de Polignac number, because 1404112212111 - 210 = 1404112211087 is a prime.
It is a super-2 number, since 2×14041122121112 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1404112252111) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12557296 + ... + 12668618.
It is an arithmetic number, because the mean of its divisors is an integer number (67038867504).
Almost surely, 21404112212111 is an apocalyptic number.
1404112212111 is a deficient number, since it is larger than the sum of its proper divisors (741131548017).
1404112212111 is a wasteful number, since it uses less digits than its factorization.
1404112212111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 112911.
The product of its (nonzero) digits is 128, while the sum is 21.
Adding to 1404112212111 its reverse (1112122114041), we get a palindrome (2516234326152).
The spelling of 1404112212111 in words is "one trillion, four hundred four billion, one hundred twelve million, two hundred twelve thousand, one hundred eleven".
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