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1404113203121 is a prime number
BaseRepresentation
bin10100011011101011101…
…010110010111110110001
311222020021001201011102012
4110123223222302332301
5141001110434444441
62553012442532305
7203305143205616
oct24335352627661
94866231634365
101404113203121
114a1532330712
121a8162807095
13a253ab12885
144bd609ca50d
15267ce2e69eb
hex146ebab2fb1

1404113203121 has 2 divisors, whose sum is σ = 1404113203122. Its totient is φ = 1404113203120.

The previous prime is 1404113203079. The next prime is 1404113203187. The reversal of 1404113203121 is 1213023114041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1113415384225 + 290697818896 = 1055185^2 + 539164^2 .

It is a cyclic number.

It is not a de Polignac number, because 1404113203121 - 230 = 1403039461297 is a prime.

It is not a weakly prime, because it can be changed into another prime (1404113200121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 702056601560 + 702056601561.

It is an arithmetic number, because the mean of its divisors is an integer number (702056601561).

Almost surely, 21404113203121 is an apocalyptic number.

It is an amenable number.

1404113203121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1404113203121 is an equidigital number, since it uses as much as digits as its factorization.

1404113203121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1404113203121 its reverse (1213023114041), we get a palindrome (2617136317162).

The spelling of 1404113203121 in words is "one trillion, four hundred four billion, one hundred thirteen million, two hundred three thousand, one hundred twenty-one".