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14041134503035 = 55352985413219
BaseRepresentation
bin1100110001010011010011…
…0101011001010001111011
31211201022121210202012211221
43030110310311121101323
53320022220413044120
645510224054132511
72646303255016303
oct314246465312173
954638553665757
1014041134503035
1145238a2414642
1216a9323651137
137ab0c5077983
1436784759a603
151953972d40aa
hexcc534d5947b

14041134503035 has 8 divisors (see below), whose sum is σ = 17167273883280. Its totient is φ = 11020965949344.

The previous prime is 14041134503023. The next prime is 14041134503063. The reversal of 14041134503035 is 53030543114041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14041134503035 is a prime.

It is a super-2 number, since 2×140411345030352 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26492706345 + ... + 26492706874.

It is an arithmetic number, because the mean of its divisors is an integer number (2145909235410).

Almost surely, 214041134503035 is an apocalyptic number.

14041134503035 is a deficient number, since it is larger than the sum of its proper divisors (3126139380245).

14041134503035 is an equidigital number, since it uses as much as digits as its factorization.

14041134503035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 52985413277.

The product of its (nonzero) digits is 43200, while the sum is 34.

Adding to 14041134503035 its reverse (53030543114041), we get a palindrome (67071677617076).

The spelling of 14041134503035 in words is "fourteen trillion, forty-one billion, one hundred thirty-four million, five hundred three thousand, thirty-five".

Divisors: 1 5 53 265 52985413219 264927066095 2808226900607 14041134503035