Base | Representation |
---|---|
bin | 11010001001110101… |
… | …01101000010011011 |
3 | 1100020112212212222012 |
4 | 31010322231002123 |
5 | 212224013011103 |
6 | 10241142220135 |
7 | 1004644506212 |
oct | 150472550233 |
9 | 40215785865 |
10 | 14041141403 |
11 | 5a559493a3 |
12 | 287a42464b |
13 | 1429cb50c3 |
14 | 972b46079 |
15 | 572a5d2d8 |
hex | 344ead09b |
14041141403 has 2 divisors, whose sum is σ = 14041141404. Its totient is φ = 14041141402.
The previous prime is 14041141351. The next prime is 14041141409. The reversal of 14041141403 is 30414114041.
14041141403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14041141403 - 220 = 14040092827 is a prime.
It is not a weakly prime, because it can be changed into another prime (14041141409) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7020570701 + 7020570702.
It is an arithmetic number, because the mean of its divisors is an integer number (7020570702).
Almost surely, 214041141403 is an apocalyptic number.
14041141403 is a deficient number, since it is larger than the sum of its proper divisors (1).
14041141403 is an equidigital number, since it uses as much as digits as its factorization.
14041141403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 14041141403 its reverse (30414114041), we get a palindrome (44455255444).
The spelling of 14041141403 in words is "fourteen billion, forty-one million, one hundred forty-one thousand, four hundred three".
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