Base | Representation |
---|---|
bin | 11010001001110101… |
… | …01101010010001011 |
3 | 1100020112212221100112 |
4 | 31010322231102023 |
5 | 212224013024121 |
6 | 10241142224535 |
7 | 1004644512152 |
oct | 150472552213 |
9 | 40215787315 |
10 | 14041142411 |
11 | 5a5594a12a |
12 | 287a42514b |
13 | 1429cb56ba |
14 | 972b46599 |
15 | 572a5d75b |
hex | 344ead48b |
14041142411 has 2 divisors, whose sum is σ = 14041142412. Its totient is φ = 14041142410.
The previous prime is 14041142393. The next prime is 14041142447. The reversal of 14041142411 is 11424114041.
14041142411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (11424114041) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14041142411 is a prime.
It is not a weakly prime, because it can be changed into another prime (14041142491) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7020571205 + 7020571206.
It is an arithmetic number, because the mean of its divisors is an integer number (7020571206).
Almost surely, 214041142411 is an apocalyptic number.
14041142411 is a deficient number, since it is larger than the sum of its proper divisors (1).
14041142411 is an equidigital number, since it uses as much as digits as its factorization.
14041142411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 512, while the sum is 23.
Adding to 14041142411 its reverse (11424114041), we get a palindrome (25465256452).
The spelling of 14041142411 in words is "fourteen billion, forty-one million, one hundred forty-two thousand, four hundred eleven".
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