14041241250013 has 4 divisors (see below), whose sum is σ = 14042186739328. Its totient is φ = 14040295760700.

The previous prime is 14041241249989. The next prime is 14041241250037. The reversal of 14041241250013 is 31005214214041.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (14041241249989) and next prime (14041241250037).

It is a cyclic number.

It is not a de Polignac number, because 14041241250013 - 2⁹ = 14041241249501 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14041241250613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 472722381 + ... + 472752082.

It is an arithmetic number, because the mean of its divisors is an integer number (3510546684832).

Almost surely, 2^{14041241250013} is an apocalyptic number.

It is an amenable number.

14041241250013 is a deficient number, since it is larger than the sum of its proper divisors (945489315).

14041241250013 is an equidigital number, since it uses as much as digits as its factorization.

14041241250013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 945489314.

The product of its (nonzero) digits is 3840, while the sum is 28.

Adding to 14041241250013 its reverse (31005214214041), we get a palindrome (45046455464054).

The spelling of 14041241250013 in words is "fourteen trillion, forty-one billion, two hundred forty-one million, two hundred fifty thousand, thirteen".