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140413433342531 is a prime number
BaseRepresentation
bin11111111011010010001100…
…110100001110101001000011
3200102011101121121000102020212
4133323102030310032221003
5121401013202413430111
61214345012450224335
741401351526516036
oct3773221464165103
9612141547012225
10140413433342531
1140816003607718
12138b90928850ab
136046c1213751b
1426960915bd01d
1511377203d498b
hex7fb48cd0ea43

140413433342531 has 2 divisors, whose sum is σ = 140413433342532. Its totient is φ = 140413433342530.

The previous prime is 140413433342519. The next prime is 140413433342659. The reversal of 140413433342531 is 135243334314041.

It is a weak prime.

It is an emirp because it is prime and its reverse (135243334314041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140413433342531 - 26 = 140413433342467 is a prime.

It is a super-2 number, since 2×1404134333425312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (140413433344531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70206716671265 + 70206716671266.

It is an arithmetic number, because the mean of its divisors is an integer number (70206716671266).

Almost surely, 2140413433342531 is an apocalyptic number.

140413433342531 is a deficient number, since it is larger than the sum of its proper divisors (1).

140413433342531 is an equidigital number, since it uses as much as digits as its factorization.

140413433342531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 622080, while the sum is 41.

Adding to 140413433342531 its reverse (135243334314041), we get a palindrome (275656767656572).

The spelling of 140413433342531 in words is "one hundred forty trillion, four hundred thirteen billion, four hundred thirty-three million, three hundred forty-two thousand, five hundred thirty-one".