Base | Representation |
---|---|
bin | 1100110001010100000101… |
… | …0100100100000011001010 |
3 | 1211201100011101221202221021 |
4 | 3030111001110210003022 |
5 | 3320023133031001302 |
6 | 45510300540303054 |
7 | 2646311410510231 |
oct | 314250124440312 |
9 | 54640141852837 |
10 | 14041344000202 |
11 | 452399a6a39a2 |
12 | 16a9381841a8a |
13 | 7ab1295a89ac |
14 | 367867331b18 |
15 | 1953aa8b7437 |
hex | cc5415240ca |
14041344000202 has 4 divisors (see below), whose sum is σ = 21062016000306. Its totient is φ = 7020672000100.
The previous prime is 14041344000197. The next prime is 14041344000217. The reversal of 14041344000202 is 20200044314041.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 10008561104161 + 4032782896041 = 3163631^2 + 2008179^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3510336000049 + ... + 3510336000052.
Almost surely, 214041344000202 is an apocalyptic number.
14041344000202 is a deficient number, since it is larger than the sum of its proper divisors (7020672000104).
14041344000202 is an equidigital number, since it uses as much as digits as its factorization.
14041344000202 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7020672000103.
The product of its (nonzero) digits is 3072, while the sum is 25.
Adding to 14041344000202 its reverse (20200044314041), we get a palindrome (34241388314243).
The spelling of 14041344000202 in words is "fourteen trillion, forty-one billion, three hundred forty-four million, two hundred two", and thus it is an aban number.
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