1404142012023 has 4 divisors (see below), whose sum is σ = 1872189349368. Its totient is φ = 936094674680.

The previous prime is 1404142011991. The next prime is 1404142012043. The reversal of 1404142012023 is 3202102414041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1404142012023 - 2⁵ = 1404142011991 is a prime.

It is a super-2 number, since 2×1404142012023² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1404142011984 and 1404142012002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1404142012043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 234023668668 + ... + 234023668673.

It is an arithmetic number, because the mean of its divisors is an integer number (468047337342).

Almost surely, 2^{1404142012023} is an apocalyptic number.

1404142012023 is a deficient number, since it is larger than the sum of its proper divisors (468047337345).

1404142012023 is an equidigital number, since it uses as much as digits as its factorization.

1404142012023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 468047337344.

The product of its (nonzero) digits is 1536, while the sum is 24.

Adding to 1404142012023 its reverse (3202102414041), we get a palindrome (4606244426064).

The spelling of 1404142012023 in words is "one trillion, four hundred four billion, one hundred forty-two million, twelve thousand, twenty-three".