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140414211213443 is a prime number
BaseRepresentation
bin11111111011010010111011…
…001011100100100010000011
3200102011110121210201100112122
4133323102323023210202003
5121401021301032312233
61214345221554514455
741401410023355206
oct3773227313444203
9612143553640478
10140414211213443
1140816372703642
12138b926b295a2b
13604700733cb7b
142696126a2793d
151137768839d98
hex7fb4bb2e4883

140414211213443 has 2 divisors, whose sum is σ = 140414211213444. Its totient is φ = 140414211213442.

The previous prime is 140414211213359. The next prime is 140414211213457. The reversal of 140414211213443 is 344312112414041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 140414211213443 - 28 = 140414211213187 is a prime.

It is a super-3 number, since 3×1404142112134433 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (140414211210443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70207105606721 + 70207105606722.

It is an arithmetic number, because the mean of its divisors is an integer number (70207105606722).

Almost surely, 2140414211213443 is an apocalyptic number.

140414211213443 is a deficient number, since it is larger than the sum of its proper divisors (1).

140414211213443 is an equidigital number, since it uses as much as digits as its factorization.

140414211213443 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36864, while the sum is 35.

Adding to 140414211213443 its reverse (344312112414041), we get a palindrome (484726323627484).

The spelling of 140414211213443 in words is "one hundred forty trillion, four hundred fourteen billion, two hundred eleven million, two hundred thirteen thousand, four hundred forty-three".