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14041525481 is a prime number
BaseRepresentation
bin11010001001111000…
…01010110011101001
31100020120121101211022
431010330022303221
5212224112303411
610241154342225
71004650666034
oct150474126351
940216541738
1014041525481
115a56090a15
12287a58a975
13142a0bab79
14972c0601b
15572ad6edb
hex344f0ace9

14041525481 has 2 divisors, whose sum is σ = 14041525482. Its totient is φ = 14041525480.

The previous prime is 14041525441. The next prime is 14041525499. The reversal of 14041525481 is 18452514041.

14041525481 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13947610000 + 93915481 = 118100^2 + 9691^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14041525481 is a prime.

It is a super-3 number, since 3×140415254813 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (14041525441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7020762740 + 7020762741.

It is an arithmetic number, because the mean of its divisors is an integer number (7020762741).

Almost surely, 214041525481 is an apocalyptic number.

It is an amenable number.

14041525481 is a deficient number, since it is larger than the sum of its proper divisors (1).

14041525481 is an equidigital number, since it uses as much as digits as its factorization.

14041525481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25600, while the sum is 35.

The spelling of 14041525481 in words is "fourteen billion, forty-one million, five hundred twenty-five thousand, four hundred eighty-one".