14042043325111 has 8 divisors (see below), whose sum is σ = 14092286812704. Its totient is φ = 13991801765760.

The previous prime is 14042043324949. The next prime is 14042043325133. The reversal of 14042043325111 is 11152334024041.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14042043325111 - 2¹³ = 14042043316919 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14042043326111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14995795 + ... + 15904651.

It is an arithmetic number, because the mean of its divisors is an integer number (1761535851588).

Almost surely, 2^{14042043325111} is an apocalyptic number.

14042043325111 is a deficient number, since it is larger than the sum of its proper divisors (50243487593).

14042043325111 is an equidigital number, since it uses as much as digits as its factorization.

14042043325111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 964121.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 14042043325111 its reverse (11152334024041), we get a palindrome (25194377349152).

The spelling of 14042043325111 in words is "fourteen trillion, forty-two billion, forty-three million, three hundred twenty-five thousand, one hundred eleven".