Base | Representation |
---|---|
bin | 1100110001010111010001… |
… | …1110011000010001011001 |
3 | 1211201102101012211102101211 |
4 | 3030111310132120101121 |
5 | 3320031412231231132 |
6 | 45510522034543121 |
7 | 2646341601260602 |
oct | 314256436302131 |
9 | 54642335742354 |
10 | 14042202211417 |
11 | 45242a0083766 |
12 | 16a9581137aa1 |
13 | 7ab235330593 |
14 | 3679092d0da9 |
15 | 19540addc147 |
hex | cc574798459 |
14042202211417 has 2 divisors, whose sum is σ = 14042202211418. Its totient is φ = 14042202211416.
The previous prime is 14042202211409. The next prime is 14042202211441. The reversal of 14042202211417 is 71411220224041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14042077420176 + 124791241 = 3747276^2 + 11171^2 .
It is a cyclic number.
It is not a de Polignac number, because 14042202211417 - 23 = 14042202211409 is a prime.
It is not a weakly prime, because it can be changed into another prime (14042202251417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7021101105708 + 7021101105709.
It is an arithmetic number, because the mean of its divisors is an integer number (7021101105709).
Almost surely, 214042202211417 is an apocalyptic number.
It is an amenable number.
14042202211417 is a deficient number, since it is larger than the sum of its proper divisors (1).
14042202211417 is an equidigital number, since it uses as much as digits as its factorization.
14042202211417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7168, while the sum is 31.
Adding to 14042202211417 its reverse (71411220224041), we get a palindrome (85453422435458).
The spelling of 14042202211417 in words is "fourteen trillion, forty-two billion, two hundred two million, two hundred eleven thousand, four hundred seventeen".
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