Base | Representation |
---|---|
bin | 11111111011011010011110… |
… | …100101100100001101000011 |
3 | 200102012020120000111200202201 |
4 | 133323122132211210031003 |
5 | 121401134403241020141 |
6 | 1214353042432454031 |
7 | 41402115013122424 |
oct | 3773323645441503 |
9 | 612166500450681 |
10 | 140422321423171 |
11 | 40819854706207 |
12 | 138ba9533aa317 |
13 | 60479ca65c938 |
14 | 2696695bbd64b |
15 | 1137a90855031 |
hex | 7fb69e964343 |
140422321423171 has 2 divisors, whose sum is σ = 140422321423172. Its totient is φ = 140422321423170.
The previous prime is 140422321423129. The next prime is 140422321423187. The reversal of 140422321423171 is 171324123224041.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-140422321423171 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 140422321423171.
It is not a weakly prime, because it can be changed into another prime (140422321423121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70211160711585 + 70211160711586.
It is an arithmetic number, because the mean of its divisors is an integer number (70211160711586).
Almost surely, 2140422321423171 is an apocalyptic number.
140422321423171 is a deficient number, since it is larger than the sum of its proper divisors (1).
140422321423171 is an equidigital number, since it uses as much as digits as its factorization.
140422321423171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64512, while the sum is 37.
The spelling of 140422321423171 in words is "one hundred forty trillion, four hundred twenty-two billion, three hundred twenty-one million, four hundred twenty-three thousand, one hundred seventy-one".
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