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14042241151 = 31452975521
BaseRepresentation
bin11010001001111101…
…11001100001111111
31100020121221202112121
431010332321201333
5212224303204101
610241221543411
71004660036401
oct150476714177
940217852477
1014042241151
115a5652a684
12287a874b67
13142a2ab843
14972d50b71
15572bc90a1
hex344fb987f

14042241151 has 4 divisors (see below), whose sum is σ = 14495216704. Its totient is φ = 13589265600.

The previous prime is 14042241149. The next prime is 14042241203. The reversal of 14042241151 is 15114224041.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15114224041 = 72159174863.

It is a cyclic number.

It is not a de Polignac number, because 14042241151 - 21 = 14042241149 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14042241131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 226487730 + ... + 226487791.

It is an arithmetic number, because the mean of its divisors is an integer number (3623804176).

Almost surely, 214042241151 is an apocalyptic number.

14042241151 is a deficient number, since it is larger than the sum of its proper divisors (452975553).

14042241151 is an equidigital number, since it uses as much as digits as its factorization.

14042241151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 452975552.

The product of its (nonzero) digits is 1280, while the sum is 25.

Adding to 14042241151 its reverse (15114224041), we get a palindrome (29156465192).

The spelling of 14042241151 in words is "fourteen billion, forty-two million, two hundred forty-one thousand, one hundred fifty-one".

Divisors: 1 31 452975521 14042241151