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140425150042313 is a prime number
BaseRepresentation
bin11111111011011101000111…
…001011111001000011001001
3200102012111212011001102202122
4133323131013023321003021
5121401211201402323223
61214354231235541025
741402245061025443
oct3773350713710311
9612174764042678
10140425150042313
114081aa76360684
12138bb40275a775
13604805b69a486
142696883733493
151137ba8d445c8
hex7fb7472f90c9

140425150042313 has 2 divisors, whose sum is σ = 140425150042314. Its totient is φ = 140425150042312.

The previous prime is 140425150042297. The next prime is 140425150042367. The reversal of 140425150042313 is 313240051524041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99255949201984 + 41169200840329 = 9962728^2 + 6416323^2 .

It is a cyclic number.

It is not a de Polignac number, because 140425150042313 - 24 = 140425150042297 is a prime.

It is a super-2 number, since 2×1404251500423132 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (140425150092313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70212575021156 + 70212575021157.

It is an arithmetic number, because the mean of its divisors is an integer number (70212575021157).

Almost surely, 2140425150042313 is an apocalyptic number.

It is an amenable number.

140425150042313 is a deficient number, since it is larger than the sum of its proper divisors (1).

140425150042313 is an equidigital number, since it uses as much as digits as its factorization.

140425150042313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 57600, while the sum is 35.

The spelling of 140425150042313 in words is "one hundred forty trillion, four hundred twenty-five billion, one hundred fifty million, forty-two thousand, three hundred thirteen".