Base | Representation |
---|---|
bin | 1100110001011010010011… |
… | …1000101110001101111111 |
3 | 1211201111110211011001210222 |
4 | 3030112210320232031333 |
5 | 3320040043143022143 |
6 | 45511134411251555 |
7 | 2646400663045616 |
oct | 314264470561577 |
9 | 54644424131728 |
10 | 14043014423423 |
11 | 45246775a5657 |
12 | 16a9769149bbb |
13 | 7ab33469aabb |
14 | 36798511887d |
15 | 195457377768 |
hex | cc5a4e2e37f |
14043014423423 has 4 divisors (see below), whose sum is σ = 14307976959768. Its totient is φ = 13778051887080.
The previous prime is 14043014423413. The next prime is 14043014423437. The reversal of 14043014423423 is 32432441034041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14043014423423 - 24 = 14043014423407 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14043014423413) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 132481268093 + ... + 132481268198.
It is an arithmetic number, because the mean of its divisors is an integer number (3576994239942).
Almost surely, 214043014423423 is an apocalyptic number.
14043014423423 is a deficient number, since it is larger than the sum of its proper divisors (264962536345).
14043014423423 is an equidigital number, since it uses as much as digits as its factorization.
14043014423423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 264962536344.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 14043014423423 its reverse (32432441034041), we get a palindrome (46475455457464).
The spelling of 14043014423423 in words is "fourteen trillion, forty-three billion, fourteen million, four hundred twenty-three thousand, four hundred twenty-three".
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