Base | Representation |
---|---|
bin | 1100110001011010101110… |
… | …0000011111001101011101 |
3 | 1211201111202120011220022212 |
4 | 3030112223200133031131 |
5 | 3320040310112323010 |
6 | 45511153420250205 |
7 | 2646403512220253 |
oct | 314265340371535 |
9 | 54644676156285 |
10 | 14043125511005 |
11 | 452472427a378 |
12 | 16a979a3a0965 |
13 | 7ab3516c41b6 |
14 | 367995b945d3 |
15 | 195461ebc505 |
hex | cc5ab81f35d |
14043125511005 has 8 divisors (see below), whose sum is σ = 17089099213824. Its totient is φ = 11076268008400.
The previous prime is 14043125510903. The next prime is 14043125511029. The reversal of 14043125511005 is 50011552134041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 14043125511005 - 222 = 14043121316701 is a prime.
It is a super-2 number, since 2×140431255110052 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19779049661 + ... + 19779050370.
It is an arithmetic number, because the mean of its divisors is an integer number (2136137401728).
Almost surely, 214043125511005 is an apocalyptic number.
It is an amenable number.
14043125511005 is a deficient number, since it is larger than the sum of its proper divisors (3045973702819).
14043125511005 is an equidigital number, since it uses as much as digits as its factorization.
14043125511005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39558100107.
The product of its (nonzero) digits is 12000, while the sum is 32.
Adding to 14043125511005 its reverse (50011552134041), we get a palindrome (64054677645046).
The spelling of 14043125511005 in words is "fourteen trillion, forty-three billion, one hundred twenty-five million, five hundred eleven thousand, five".
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