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14043212143 = 23933765393
BaseRepresentation
bin11010001010000101…
…00110100101101111
31100020200210002111021
431011002212211233
5212230030242033
610241254435011
71005001222312
oct150502464557
940220702437
1014043212143
115a57033154
12287b062a67
13142a55b7ac
14973124979
15572d1bb2d
hex3450a696f

14043212143 has 8 divisors (see below), whose sum is σ = 14655580128. Its totient is φ = 13430993664.

The previous prime is 14043212123. The next prime is 14043212149. The reversal of 14043212143 is 34121234041.

14043212143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14043212143 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14043212149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 182055 + ... + 247447.

It is an arithmetic number, because the mean of its divisors is an integer number (1831947516).

Almost surely, 214043212143 is an apocalyptic number.

14043212143 is a deficient number, since it is larger than the sum of its proper divisors (612367985).

14043212143 is an equidigital number, since it uses as much as digits as its factorization.

14043212143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 74753.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14043212143 its reverse (34121234041), we get a palindrome (48164446184).

The spelling of 14043212143 in words is "fourteen billion, forty-three million, two hundred twelve thousand, one hundred forty-three".

Divisors: 1 23 9337 65393 214751 1504039 610574441 14043212143