140440331130001 has 4 divisors (see below), whose sum is σ = 160503235577152. Its totient is φ = 120377426682852.

The previous prime is 140440331129983. The next prime is 140440331130097. The reversal of 140440331130001 is 100031133044041.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140440331130001 - 2¹³ = 140440331121809 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140440331130601) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10031452223565 + ... + 10031452223578.

It is an arithmetic number, because the mean of its divisors is an integer number (40125808894288).

Almost surely, 2^{140440331130001} is an apocalyptic number.

It is an amenable number.

140440331130001 is a deficient number, since it is larger than the sum of its proper divisors (20062904447151).

140440331130001 is an equidigital number, since it uses as much as digits as its factorization.

140440331130001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20062904447150.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 140440331130001 its reverse (100031133044041), we get a palindrome (240471464174042).

The spelling of 140440331130001 in words is "one hundred forty trillion, four hundred forty billion, three hundred thirty-one million, one hundred thirty thousand, one".