Base | Representation |
---|---|
bin | 1000001011001011111… |
… | …0000000000011001111 |
3 | 111102111121112222220222 |
4 | 2002302332000003033 |
5 | 4300111014113210 |
6 | 144303513501555 |
7 | 13101162326111 |
oct | 2026276000317 |
9 | 442447488828 |
10 | 140441551055 |
11 | 54619659a73 |
12 | 232757118bb |
13 | 103221c1100 |
14 | 6b2412b3b1 |
15 | 39be891655 |
hex | 20b2f800cf |
140441551055 has 24 divisors (see below), whose sum is σ = 182547023760. Its totient is φ = 103678798080.
The previous prime is 140441551043. The next prime is 140441551057. The reversal of 140441551055 is 550155144041.
It is not a de Polignac number, because 140441551055 - 220 = 140440502479 is a prime.
It is a super-2 number, since 2×1404415510552 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (140441551057) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2926091 + ... + 2973699.
It is an arithmetic number, because the mean of its divisors is an integer number (7606125990).
Almost surely, 2140441551055 is an apocalyptic number.
140441551055 is a deficient number, since it is larger than the sum of its proper divisors (42105472705).
140441551055 is a wasteful number, since it uses less digits than its factorization.
140441551055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51131 (or 51118 counting only the distinct ones).
The product of its (nonzero) digits is 40000, while the sum is 35.
Adding to 140441551055 its reverse (550155144041), we get a palindrome (690596695096).
The spelling of 140441551055 in words is "one hundred forty billion, four hundred forty-one million, five hundred fifty-one thousand, fifty-five".
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